Why does the object created and returned by the function continue to exist after the completion of the function?

Question

I read that each function has its own stack, which means that when a function ends, its variables are no longer stored in memory. I also read that objects are returned by reference.

Consider the following example:

function getObject() {
 var obj = {name: "someName"};
 return obj;
} //At the end the locals should disappear


var newObj = getObject();// Get reference to something that is no longer kept in the stack,
console.log(newObj);//

Run code

So, if the return value of the function is a reference for an object that no longer exists (on the stack), how do we still get the correct value? In C(language), to return a pointer to a local variable is insane.

Answer 1

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                    +−−−−−−−−−−−−−−−−−−+
                    |     (object)     |
                    +−−−−−−−−−−−−−−−−−−+
[obj:Ref11254]−−−−−>| name: "someName" |
                    +−−−−−−−−−−−−−−−−−−+

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:

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function getFunction() {
    var x = 0;
    return function() {
        return x++;
    };
}
var f = getFunction();
console.log(f()); // 0
console.log(f()); // 1
console.log(f()); // 2

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Answer 2

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., , https://developer.mozilla.org/en-US/docs/Web/JavaScript/Memory_Management