Taking the address of a function from within this function

Question

Firstly, the question is: is there a reason why you cannot take the address of a function from this function?

#include <stdio.h>

struct foo {
  void(*xf)(void);
  int r;
} sFoo;

void func(void) {
  sFoo.xf = func; /* <-- like this */
}

int main()
{
  func();
  printf("FuncPtr  is: %p\n", sFoo.xf);
  printf("FuncAddr is: %p\n", &func);
  getchar();
  return 0;
}

I cannot think of the reason why this should not work portable, but that does not mean that it does not exist. I tested it with MinGW and MSVC on Windows, and gcc on Ubuntu, and it works great. Standard C is almost silent, except that (C99 5.1.1.2) function references are resolved in the final translation phase.

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Answer 1

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Answer 2

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