Get the last div with the same data attribute

Question

How can I select the last div from div groups with the same data id? I tried using .last and getting the last div with: contains, but didn't work.

HTML:

<div class="rentals_reservation" data-id="3407">Booking id: 3407</div>
<div class="rentals_reservation" data-id="3407">Booking id: 3407</div>
*<div class="rentals_reservation" data-id="3407">Booking id: 3407</div>
<div class="rentals_reservation" data-id="3227">Booking id: 3227</div>
<div class="rentals_reservation" data-id="3227">Booking id: 3227</div>
*<div class="rentals_reservation" data-id="3227">Booking id: 3227</div>

JQuery

$(".rentals_reservation").each(function(i, value) {
        var id = $(value).attr("data-id").;
        console.log(id);
    })

Answer 1

This is not entirely clear from the question, but it looks like you want to select all the latest divs from those that have the same data identifier. those. 2 that you marked "*".

You can:

• get a unique list of identifiers
• to return items

the picture below does this and hides the elements (to show that they selected them).

//https://stackoverflow.com/a/33121880/2181514
var ids = $(".rentals_reservation").map(function() { return $(this).data("id"); }).toArray();
var uniqueids =  [...new Set(ids)]
var lastdivs = $(uniqueids).map(function() { return $("[data-id=" + this + "]").last()[0] });
$(lastdivs).hide();

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div class="rentals_reservation" data-id="3407">Booking id: 3407</div>
<div class="rentals_reservation" data-id="3407">Booking id: 3407</div>
<div class="rentals_reservation" data-id="3407">Booking id: 3407*</div>
<div class="rentals_reservation" data-id="3227">Booking id: 3227</div>
<div class="rentals_reservation" data-id="3227">Booking id: 3227</div>
<div class="rentals_reservation" data-id="3227">Booking id: 3227*</div>

Run codeHide result

Answer 2

Well, you can make a selector and select the elements and select the last

console.log($('[data-id="' + id + '"]').last())

Answer 3

. - . "" data-id:

var dataIdsMap = {};
$(".rentals_reservation").each(function(i, value) {
        var id = $(value).attr("data-id").;
        dataIdsMap[id] = $(value);

    })
 console.log(dataIdsMap);

Answer 4

, , , id.

var $allReservations = $('.rentals_reservation');

console.log(
$allReservations.map(function getTheIds(){
  return this.getAttribute('data-id');
}).get().reduce(function getTheUniqueIds(collection, element){
  if (collection.indexOf(element) < 0) collection.push(element);
  return collection;
}, []).map(function findTheLastElementForEachId(element){
  return $allReservations.filter('[data-id="'+ element +'"]').last();
})
);

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div class="rentals_reservation" data-id="3407">Booking id: 3407</div>
<div class="rentals_reservation" data-id="3407">Booking id: 3407</div>
*<div class="rentals_reservation" data-id="3407">Booking id: 3407</div>
<div class="rentals_reservation" data-id="3227">Booking id: 3227</div>
<div class="rentals_reservation" data-id="3227">Booking id: 3227</div>
*<div class="rentals_reservation" data-id="3227">Booking id: 3227</div>

Hide result

Answer 5

, , array , , , id , div id:

var existingIds=[];
var selectedElements=[];
$(".rentals_reservation").each(function(i, value) {
        
         if( !existingIds.includes($(value).data("id")) )
         {
           existingIds.push($(value).data("id"));
          
           selectedElements.push($(".rentals_reservation[data-id='"+$(value).data("id")+"']:last"));
         }         
    })
    console.log(existingIds);
    $.each(selectedElements,function(index, element){
     console.log($(element).text());
    
    })

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div class="rentals_reservation" data-id="3407">1.Booking id: 3407</div>
<div class="rentals_reservation" data-id="3407">2.Booking id: 3407</div>
<div class="rentals_reservation" data-id="3407">3.Booking id: 3407</div>
<div class="rentals_reservation" data-id="3227">1.Booking id: 3227</div>
<div class="rentals_reservation" data-id="3227">2.Booking id: 3227</div>
<div class="rentals_reservation" data-id="3227">3.Booking id: 3227</div>

Hide result

Answer 6

. ;

var last = $(".rentals_reservation").last().data("id");
var values = [];
$(".rentals_reservation").each(function(i, v){
  if($(this).data("id") === last){
    values.push($(this).data("id"));
  }
})

console.log(values);

#result{
  color: #F00;
}

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>


<div class="rentals_reservation" data-id="3407">Booking id: 3407</div>
<div class="rentals_reservation" data-id="3407">Booking id: 3407</div>
*<div class="rentals_reservation" data-id="3407">Booking id: 3407</div>
<div class="rentals_reservation" data-id="3227">Booking id: 3227</div>
<div class="rentals_reservation" data-id="3227">Booking id: 3227</div>
*<div class="rentals_reservation" data-id="3227">Last One Booking id: 3227</div>

<br /><br />
<div id="result"></div>

Hide result