How to iterate over sentence words in C ++?

Question

My input is "Hello World" and my target result is "olleH dlroW".

So, my idea is to get the sentence into a variable, and then iterate over the words in the sentence, cancel each of them, and finally merge them into a new variable.

My question is: how to iterate over sentence words?

#include <iostream>
#include <stdio.h>
#include <string.h>
using namespace std;

string reverseword(string word)
{
    string rword;
    int size = word.length();
    while (size >= 0)
    {
        rword+= word[size];
        size = size -1;
    }   
    return rword;
}

int main()
{ 
    string sentence;
    cout<<"Enter the word/sentence to be reversed: ";
    cin >> sentence;
    string rsentence;
    // for every word in the sentence do
    {
        rword = reverseword(word);
        rsentence = rsentence + " " + rword; 
    }
    cout<<rword;
    return 0;
}

Answer 1

Before you can iterate over words in a sentence, you need to read the sentence from the input. This line

cin >> sentence;

reads the first word of a sentence, not the whole sentence. Use instead getline:

std::getline(std::cin, sentence);

With sentencein memory, you can iterate over it sequentially using istream_iteratoras follows:

stringstream ss(sentence);
for (auto w = istream_iterator<string>(ss) ; w != istream_iterator<string>() ; w++) {
    string &word = *w;
    ...
}

Demo version

Answer 2

   for(short i=0;i<sentence.length();i++){

        if(sentence[i] == ' '){
            counter++;
            i++;
        }

        words[counter] += sentence[i];
    }

, , words[]

#include <iostream>
#include <stdio.h>
#include <string.h>

using namespace std;

string reverseword(string word) // function to reverse a word
{
    string rword;
    int size = word.length();
    while (size >= 0)
    {
        rword+= word[size];
        size = size -1;
    }   
    return rword;
}

int main()
{ 
    string sentence;

    cout << "Enter the word/sentence to be reversed: ";
    std::getline(std::cin, sentence);


    string rsentence;
    string words[100];


    string rword;

    short counter = 0;

    for(short i=0; i<sentence.length(); i++){ // looping till ' ' and adding each word to string array words

        if(sentence[i] == ' '){
            counter++;
            i++;
        }

        words[counter] += sentence[i];
    }



    for(int i = 0; i <= counter; i++) // calling reverse function for each words
    {
        rword = reverseword(words[i]);

        rsentence = rsentence + " " + rword;  // concatenating reversed words
    }

    cout << rsentence; // show reversed word

    return 0;
}

. , ...!!

NB: cin , . std::getline(std::cin, sentence) .

std::reverse()

Answer 3

, find reverse :

#include <iostream>
#include <string>
#include <algorithm>


int main() {
    std::string sentence;
    std::getline(std::cin, sentence);
    std::cout << sentence << std::endl;
    size_t cpos = 0;
    size_t npos = 0;
    while((npos = sentence.find(' ', cpos)) != std::string::npos)
    {
        std::reverse(sentence.begin() + cpos, sentence.begin() + npos);
        cpos = npos + 1;
    }
    std::reverse(sentence.begin() + cpos, sentence.end());
    std::cout << sentence << std::endl;
    return 0;
}

Input:

this is a nice day

:

this is a nice day
siht si a ecin yad

Answer 4

, ? () ,

Answer 5

, , , .. cin >> sentence ( ).

, "". - - - . , , , . , "", , split (cin >> word)

, , (, ) . Regex word (, "\ w +" ).

"" , . , ( split, Regex - ) .

, "" , .

Answer 6

Boost boost::split:

#include <iostream>
#include <vector>
#include <string>
#include <algorithm>
#include <boost/algorithm/string.hpp>

int main()
{
    std::string sentence = "Hello world";

    std::vector<std::string> words;
    boost::split(words, sentence, boost::is_any_of(" "));

    std::string rsentence;
    for (std::string word : words) // Iterate by value to keep the original data.
    {
        std::reverse(word.begin(), word.end());
        rsentence += word + " "; // Add the separator again.
    }
    boost::trim(rsentence); // Remove the last space.

    std::cout << rsentence << std::endl;

    return 0;
}

Answer 7

- .

#include <string>                                                            
#include <iostream>                                                          
#include <algorithm>                                                         
#include <cctype>                                                            

int main()                                                                   
{                                                                            
    std::string sentence;                                                    
    while (std::getline(std::cin, sentence))                                 
    {                                                                        
        auto ws = sentence.begin();                                          

        while (ws != sentence.end())                                         
        {                                                                    
            while (std::isspace(*ws)) ++ws;                                  
            auto we = ws;                                                    
            while (we != sentence.end() && !std::isspace(*we)) ++we;         
            std::reverse(ws, we);                                            
            ws = we;                                                         
        }                                                                    
        std::cout << sentence << "\n";                                       
    }                                                                        
}

This suggests that the word "is defined" as "a sequence of characters without spaces". It is easy to substitute a different class of characters instead of "non-spaces", for example. for alphanumeric characters use std::isalnum. A definition that reflects the real concept of a word, for example. used in the natural language sciences goes far beyond the scope of this answer.