In the following code, I am trying to combine 2 Producerinto 1. Everyone is of the same type. They will be combined by each of the two inputs Producer, executed in a separate thread and consumed Consumer, which puts the values in the unagi chan (I use unagi chan for performance). The producer that reads from chan returns. I want to be able to use any Producerif it can run IO, so I am restricting the monad class to MonadIOand HasFork.
import Pipes (Producer, Consumer, (>->), yield, await, runEffect)
import Control.Concurrent.Chan.Unagi (InChan, OutChan, newChan, readChan, writeChan)
import Control.Monad (forever, void)
import Control.Concurrent.MonadIO (MonadIO, HasFork, liftIO, fork)
combine :: (MonadIO m, HasFork m) => Producer a m r -> Producer a m r -> Producer a m r
combine p1 p2 = do
(inChan, outChan) <- liftIO $ newChan
t1 <- fork . void . runEffect $ p1 >-> (consumer inChan)
t2 <- fork . void . runEffect $ p2 >-> (consumer inChan)
producer outChan
producer :: (MonadIO m) => OutChan a -> Producer a m r
producer outChan = forever $ do
msg <- liftIO $ readChan outChan
yield msg
consumer :: (MonadIO m) => InChan a -> Consumer a m r
consumer inChan = forever $ do
msg <- await
liftIO $ writeChan inChan msg
However, I get the following error:
• Couldn't match type ‘m’
with ‘Pipes.Internal.Proxy Pipes.Internal.X () () a m’
‘m’ is a rigid type variable bound by
the type signature for:
combine :: forall (m :: * -> *) a r.
(MonadIO m, HasFork m) =>
Producer a m r -> Producer a m r -> Producer a m r
at src/Pipes/Unagi.hs:8:12
Expected type: Pipes.Internal.Proxy
Pipes.Internal.X () () a m GHC.Conc.Sync.ThreadId
Actual type: m GHC.Conc.Sync.ThreadId
Am I trying to do this?
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