I am trying to read a txt file, which is like a different number of columns in a row. Here is the beginning of my file:
60381 6
1 0.270 0.30 0.30 0.70 0.70
4.988 4.988 4.988 4.988 4.988 4.988 4.988 4.988 4.988 4.988 4.988 4.988
2 0.078 0.30 0.30 0.70 0.70
5.387 5.312 5.338 4.463 4.675 4.275 4.238 3.562 3.175 3.925 4.950 4.762
6 0.241 0.30 0.60 0.70 0.40
3.700 3.200 2.738 2.325 1.250 0.975 1.175 1.950 2.488 3.613 3.987 3.950
7 0.357 0.30 0.60 0.70 0.40
1.212 1.125 1.050 0.950 0.663 0.488 0.425 0.512 0.637 0.900 1.112 1.188
8 0.031 0.30 0.70 0.70 0.30
0.225 0.213 0.200 0.175 0.200 0.213 0.375 0.887 0.975 0.512 0.262 0.262
10 0.022 0.30 0.80 0.70 0.20
0.712 0.700 0.738 0.550 0.513 0.688 0.613 0.600 0.850 0.812 0.800 0.775
60382 5
6 0.197 0.30 0.60 0.70 0.40
3.700 3.200 2.738 2.325 1.250 0.975 1.175 1.950 2.488 3.613 3.987 3.950
7 0.413 0.30 0.60 0.70 0.40
1.212 1.125 1.050 0.950 0.663 0.488 0.425 0.512 0.637 0.900 1.112 1.188
8 0.016 0.30 0.70 0.70 0.30
0.225 0.213 0.200 0.175 0.200 0.213 0.375 0.887 0.975 0.512 0.262 0.262
10 0.111 0.30 0.80 0.70 0.20
0.712 0.700 0.738 0.550 0.513 0.688 0.613 0.600 0.850 0.812 0.800 0.775
11 0.263 0.30 0.50 0.70 0.50
1.812 1.388 1.087 0.825 0.538 0.400 0.338 0.400 0.500 0.925 0.962 1.100
I tried using pandas read_csv to read it:
import pandas as pd
data = pd.read_csv('./myfile.txt',header=None,sep='\s')
Which gives the following error:
ParserError: Expected 6 fields in line 3, saw 12. Error could possibly be due to quotes being ignored when a multi-char delimiter is used.
Thus, my file does not have a separator or multi-char quotation marks. I tried the solution for this that I found on this forum, which suggested using:
data = pd.read_csv(open('./myfile.txt','r'), header=None,encoding='utf-8', engine='c')
Although this solves the error above, the array I represent does not use space as a column separator, and the output has only 1 column:

How should I read the file to get a column for each value? I do not mind if there are nanny values that fill the rest.
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