Why is it for std :: to forward called calls before the call?

Question

Often people std::forwardcall the object before calling it ( example ):

template <typename F, typename ...Args>
void call(F &&f, Args &&...args)
{
    std::forward<F>(f) ( // <<< -- question
        std::forward<Args>(args)...  
    );
}

What is the advantage of std::forward-ing fin the above example over a simple one f(std::forward<Args>(args)...?