I am using AWS SES and trying to attach a zip file to a CSV email that is made in memory. I'm close, but it's hard for me to understand this. Currently, when I receive an email, I still receive .CSV, but when opened it seems that the contents are compressed. How to make a zip file, not content? The file is currently accepted as a bye array.
public void emailReport(byte[] fileAttachment, String attachmentType,
String attachmentName, List<String> emails) throws MessagingException, IOException {
......
messageBodyPart = new MimeBodyPart();
byte[] test = zipBytes(attachmentName, fileAttachment);
DataSource source = new ByteArrayDataSource(test, "application/zip");
messageBodyPart.setDataHandler(new DataHandler(source));
messageBodyPart.setFileName(attachmentName);
multipart.addBodyPart(messageBodyPart);
log.info("Successfully attached file.");
message.setContent(multipart);
try {
ByteArrayOutputStream outputStream = new ByteArrayOutputStream();
message.writeTo(outputStream);
RawMessage rawMessage = new RawMessage(ByteBuffer.wrap(outputStream.toByteArray()));
SendRawEmailRequest rawEmailRequest = new SendRawEmailRequest(rawMessage);
client.sendRawEmail(rawEmailRequest);
System.out.println("Email sent!");
log.info("Email successfully sent.");
} catch (Exception ex) {
log.error("Error when sending email");
ex.printStackTrace();
}
}
zip byte function
public static byte[] zipBytes(String filename, byte[] input) throws IOException {
ByteArrayOutputStream baos = new ByteArrayOutputStream();
ZipOutputStream zos = new ZipOutputStream(baos);
ZipEntry entry = new ZipEntry(filename);
entry.setSize(input.length);
zos.putNextEntry(entry);
zos.write(input);
zos.closeEntry();
zos.close();
return baos.toByteArray();
}
Thanks for the help, if you have additional questions, please let me know and I will provide any code, etc. necessary.
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