Reading two long sentences with scanf

Question

I want to read two long sentences from input using scanf()which are in two new lines.

The code:

int main() {
    char a[100], b[100];
    scanf("%[^\n]s", a);
    scanf("%[^\n]s", b);
    printf("%s\n%s", a, b);
}

Input:

she is beautiful
That is a flower

Conclusion:

she is beautiful

The second input is not read by the operator scanf().

How to fix it?

Answer 1

You can use fgets. And that might work for you.

#include <stdio.h>
#include <stdint.h>

int main() {
    char a[100], b[100];

    if (fgets(a, sizeof a, stdin) == NULL) {
        puts("fgets error");
        return -1;
    }

    if (fgets(b, sizeof b, stdin) == NULL) {   //Read blank lines 
        puts("fgets error");
        return -1;
    }

    if (fgets(b, sizeof b, stdin) == NULL) {
        puts("fgets error");
        return -1;
    }

    printf("%s\n%s", a, b);

    return 0;
}

Answer 2

For this you need the correct answer. If you insist on using scanf(), there will be only one line of format, which will be safe and do what you want:

int main() {
    char a[100] = "";
    char b[100] = "";
    scanf("%99[^\n]%*c", a);
    scanf("%99[^\n]%*c", b);
    printf("%s\n%s", a, b);
}

[^\n]s, , [^\n] , -, . , s.

- 99. 99 - 0, 100 , . , 99 , .

- %*c: %c , , %[^\n]. , . *, .

---

, fgets(), , :

int main() {
    char a[100] = "";
    char b[100] = "";
    fgets(a, 100, stdin);
    fgets(b, 100, stdin);

    // if needed, strip newlines, e.g. like this:
    size_t n = strlen(a);
    if (n && a[n-1] == '\n') a[--n] = 0;
    n = strlen(b);
    if (n && b[n-1] == '\n') b[--n] = 0;


    printf("%s\n%s", a, b);
}

Answer 3

int main(){

    char a[100];

    while (scanf("%[^\n]%*c", a)==1) {
     printf("%s\n",a); 
    }
    return 0;
  }