Swift sorts an array and returns an array of index and element

Question

I want to sort an array and return an array of indices and elements in a sorted array;

t

var filtered = self.existingOrders.sorted(by: { (eo1:ExistingOrder, eo2:ExistingOrder) -> Bool in
                return (eo1.value < eo2.value)
            }).index(0, offsetBy: 0)

It just gives me the index of a specific number.

I need a sorted array of elements and indexes; so I can grab the necessary index and do manipulations on them.

How to do this so that I can:

// pseduocode:

var filtered:(Index, Element) = self.existingOrders.sortByLowest.return(flatMap(index, element))

or perhaps even an enumerator to give me a list of all indexed items; after sorting?

t

 let filtered = self.existingOrders.sorted(by: { (eo1:ExistingOrder, eo2:ExistingOrder) -> Bool in
                return (eo1.value < eo2.value)
            }).enumerated().flatMap({ (offset:Int, element:ExistingOrder) -> (Int, ExistingOrder) in
                return (offset, element)
            })

I want to get a sorted array and return the index and element in my filter variable.

How to do it?

Many thanks

Answer 1

, enumerated(), offset/element sort . :

let array = ["C", "A", "B"]

let sortedElementsAndIndices = array.enumerated().sorted(by: {
    $0.element < $1.element
})

print(sortedElementsAndIndices) // [(1, "A"), (2, "B"), (0, "C")]

.

-

let sorted = self.existingOrders.enumerated().sorted(by: {
    $0.element.value < $1.element.value
})