Python3 typing: extract argument list from Callable

Question

Consider a function that wraps another function and outputs the output to a singleton list:

def listify(func):
    return lambda *kargs, **kwargs: [func(*kargs, **kwargs)]

How would you type - call this function in python3? This is my best attempt:

from typing import Callable, TypeVar
T = TypeVar('T')

def listify(func: Callable[..., T]) -> Callable[..., List[T]]:
    return lambda *kargs, **kwargs: [func(*kargs, **kwargs)]

But I'm not glad that the returned one Callabledoes not inherit the signature of the input argument types Callable. Is there a way to do this without making assumptions about the number of arguments func?

Answer 1

You cannot do what you want with a hint of type. There is no syntax for writing part of arguments in TypeVargeneric.

Callable , . , , ( ...). ArgumentsVar, , .

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