Sort an array of objects based on a key and based on a value

Question

Consider this:

[{name:'John'},{age:25},{address:'some street'}]

As you can see, none of the keys is a consistent name, so I can not use.

arr.sort((a,b)=> a.consistentKey < b.consistentKey);

How can I sort something like this, by name and by value?

therefore, the following sorting by key in alphabetical order should be:

[{address:'some street'},{age:25},{name:'John'}]

Answer 1

If you are thinking about sorting based on the key first, and then by value, you can try the following:

var a = [{name:'John'},{age:25},{address:'some street'}];
        
    alert(JSON.stringify(a.sort((a, b) => {
      nameA = Object.keys(a)[0];
      nameB = Object.keys(b)[0];
    
      if (nameA < nameB) {
        return -1;
      }
      if (nameA > nameB) {
        return 1;
      }
    
      // names must be equal
      return 0;
    })));

Run code

Here I examined only one key, but you can always expand it to several keys, and in the same way, you can additionally sort based on values.

Answer 2

Object.keys, , :

[{name: 'John'}, {age: 25}, {address:'some street'}].sort((a, b) => {
  const keyA = Object.keys(a)[0]
  const valA = a[keyA]
  const keyB = Object.keys(b)[0]
  const valB = a[keyB]

  if (keyA > keyB) {
    return 1
  } else if (keyA < keyB) {
    return -1
  } else /* equal */ {
   if (valA > valB) {
      return 1
    } else if (valA < valB) {
      return -1
    } else /* equal */ {
      return 0
    }
  }
})

Answer 3

input.sort((a, b) => {
  const keya = Object.keys(a)[0];
  const keyb = Object.keys(b)[0];

  return keya.localeCompare(keyb) || a[keya].localeCompare(b[keyb]);
});

localeCompare .

Answer 4

, . , , , .

class FunkySort {
  sort (sortType) {
    switch (sortType) {
      case 'keysOnly':
        return data => this._sortByKey(data);
      case 'valuesOnly':
        return data => this._sortByValue(data);
      case 'valuesPrimary':
        return data => {
          data = this._sortByKey(data);
          return this._sortByValue(data);
        };
      case 'keysPrimary':
        return data => {
          data = this._sortByValue(data);
          return this._sortByKey(data);
        };
    }
  }

  _sortByKey (data) {
    return data.sort((a, b) => {
      var keyA = Object.keys(a)[0];
      var keyB = Object.keys(b)[0];
      return keyA < keyB ? -1 : keyA > keyB ? 1 : 0;
    });
  }

  _sortByValue (data) {
    return data.sort((a, b) => {
      // note that in Node >=v7 you could use `Object.values()`, but not in <v7.0
      var valueA = a[Object.keys(a)[0]];
      var valueB = b[Object.keys(b)[0]];
      return valueA < valueB ? -1 : valueA > valueB ? 1 : 0;
    });
  }
}

const dataArr = [{name:'John'},{age:25},{address:'some street'}];
const fs = new FunkySort();
fs.sort('keysPrimary')(dataArr);

, fs.sort . , , fs.sort('keysPrimary') , , , , , , .

If you do not need this level of flexibility in the sort type, then just a helper method is enough _sortByKey.