Scrapy request return notImplementedError

Question

My scrapy code doesn't work, and I have no idea! I want to clean up the Ikea site, I developed CrawlSpider first, which was not specific enough to retrieve all the links to a web page. Therefore, I developed a basic Spider with a yield request method.

Here is my code:

class IkeaSpider(scrapy.Spider) :        
    name = "Ikea"
    allower_domains = ["http://www.ikea.com/"]
    start_urls = ["http://www.ikea.com/fr/fr/catalog/productsaz/8/"]



    def parse_url(self, response):

        for sel in response.xpath('//div[@id="productsAzLeft"]'):

            base_url = 'http://www.ikea.com/'
            follow_url = sel.xpath('//span[@class="productsAzLink"]/@href').extract()
            complete_url = urlparse.urljoin(base_url, follow_url)
            request = Request(complete_url, callback = self.parse_page)

            yield request


    def parse_page(self, response):

And here is the error log:

2016-01-04 22:06:31 [scrapy] ERROR: Spider error processing <GET http://www.ikea.com/fr/fr/catalog/productsaz/8/> (referer: None)
Traceback (most recent call last):
  File "/usr/local/lib/python2.7/dist-packages/twisted/internet/defer.py", line 588, in _runCallbacks
    current.result = callback(current.result, *args, **kw)
  File "/usr/local/lib/python2.7/dist-packages/scrapy/spiders/__init__.py", line 76, in parse
    raise NotImplementedError
NotImplementedError

Answer 1

Your spider needs a method parse, which is the default callback for all initial requests. You can simply rename the method parse_urlto parse, and it will work just fine.

class IkeaSpider(scrapy.Spider) :

    name = "Ikea"
    allower_domains = ["http://www.ikea.com/"]
    start_urls = ["http://www.ikea.com/fr/fr/catalog/productsaz/8/"]


    def parse(self, response):

        for sel in response.xpath('//div[@id="productsAzLeft"]'):

            base_url = 'http://www.ikea.com/'
            follow_url = sel.xpath('//span[@class="productsAzLink"]/@href').extract()
            complete_url = urlparse.urljoin(base_url, follow_url)
            request = Request(complete_url, callback = self.parse_page)

            yield request

Alternatives

start_requests scrapy.Requests callback, .

Answer 2

parse, start_urls ,

parse , URL- start_urls.

, start_requests.