How can I run the if run from ipython test in Python?

Question

To make debugging easier with Ipython, I include the following at the beginning of my scripts

from IPython.Debugger import Tracer
debug = Tracer()

However, if I run my script from the command line using

$ python myscript.py

I am getting an error related to Ipython. Is there any way to do the following

if run_from_ipython():
    from IPython.Debugger import Tracer
    debug = Tracer()

That way, I only import the Tracer () function when I need it.

Answer 1

This is probably what you are looking for:

def run_from_ipython():
    try:
        __IPYTHON__
        return True
    except NameError:
        return False

Answer 2

Python's way is to use exceptions. How:

try:
    from IPython.Debugger import Tracer
    debug = Tracer()
except ImportError:
    pass # or set "debug" to something else or whatever

Answer 3

, ( __IPYTHON__) -

def in_ipython():
    return hasattr(globals()["__builtins__"], "__IPYTHON__")

, Tom Dunham:

from timeit import timeit
timeit(in_ipython, number=100000)
> 0.026131024002097547

def toms_in_ipython():
    try:
        return __IPYTHON__
    except NameError:
        return False

timeit(toms_in_ipython, number=100000)
> 0.013109331019222736