Top k columns with values ​​in pandas dataframe for each row

Question

I have a pandas dataframe as shown below:

   A  B  C  D
0  7  2  5  2
1  3  3  1  1
2  0  2  6  1
3  3  6  2  9

There may be 100 columns, in the above example, I showed only 4.

I would like to extract the top k columns for each row and their values.

I can get top-k columns using:

pd.DataFrame({n: df.T[column].nlargest(k).index.tolist() for n, column in enumerate(df.T)}).T

which for k = 3 gives:

   0  1  2
0  A  C  B
1  A  B  C
2  C  B  D
3  D  B  A

But I would like to:

   0  1  2  3  4  5
0  A  7  C  5  B  2
1  A  3  B  3  C  1
2  C  6  B  2  D  1
3  D  9  B  6  A  3

Is there a pand (a) way to achieve this?

Answer 1

You can use the solution numpy:

• numpy.argsort for column names
• the array is already sorted (thanks Jeff ), you needvalues by indices
• interweave for a new array
• DataFrame constructor

k = 3
vals = df.values
arr1 = np.argsort(-vals, axis=1)

a = df.columns[arr1[:,:k]]
b = vals[np.arange(len(df.index))[:,None], arr1][:,:k]

c = np.empty((vals.shape[0], 2 * k), dtype=a.dtype)
c[:,0::2] = a
c[:,1::2] = b
print (c)
[['A' 7 'C' 5 'B' 2]
 ['A' 3 'B' 3 'C' 1]
 ['C' 6 'B' 2 'D' 1]
 ['D' 9 'B' 6 'A' 3]]

df = pd.DataFrame(c)
print (df)
   0  1  2  3  4  5
0  A  7  C  5  B  2
1  A  3  B  3  C  1
2  C  6  B  2  D  1
3  D  9  B  6  A  3

Answer 2

>>> def foo(x):
...     r = []
...     for p in zip(list(x.index), list(x)):
...             r.extend(p)
...     return r
... 
>>> pd.DataFrame({n: foo(df.T[row].nlargest(k)) for n, row in enumerate(df.T)}).T
   0  1  2  3  4  5
0  A  7  C  5  B  2
1  A  3  B  3  C  1
2  C  6  B  2  D  1
3  D  9  B  6  A  3

Or using a list comprehension:

>>> def foo(x):
...     return [j for i in zip(list(x.index), list(x)) for j in i]
... 
>>> pd.DataFrame({n: foo(df.T[row].nlargest(k)) for n, row in enumerate(df.T)}).T
   0  1  2  3  4  5
0  A  7  C  5  B  2
1  A  3  B  3  C  1
2  C  6  B  2  D  1
3  D  9  B  6  A  3

Answer 3

This does the job efficiently: it uses argpartition, which finds the n largest in O (n), and then only sorts them.

values=df.values
n,m=df.shape
k=4
I,J=mgrid[:n,:m]
I=I[:,:1]
if k<m: J=(-values).argpartition(k)[:,:k]
values=values[I,J]
names=np.take(df.columns,J)
J2=(-values).argsort()
names=names[I,J2]
values=values[I,J2]
names_and_values=np.empty((n,2*k),object)
names_and_values[:,0::2]=names
names_and_values[:,1::2]=values
result=pd.DataFrame(names_and_values)

For

   0  1  2  3  4  5
0  A  7  C  5  B  2
1  B  3  A  3  C  1
2  C  6  B  2  D  1
3  D  9  B  6  A  3