Can "static const char array" include a member of a variable in C

Question

My code is as follows

#include <stdio.h>

static const char *a ="this is a";
static const char *b ="this is b";

char *comb_ab[2] =
{
    a,
    b
};

int main() {

    int i=0;

    for(i=0; i<sizeof(comb_ab)/sizeof(comb_ab[0]); i++) {
        printf("%s\n",comb_ab[i]);
    }
}

this code works with the g ++ compiler (C ++). but gcc doesn't work. the conclusion is as follows

test.c:8:2: error: initializer element is not constant
  a,
  ^
test.c:8:2: error: (near initialization for ‘comb_ab[0]’)
test.c:10:1: error: initializer element is not constant
 };
 ^
test.c:10:1: error: (near initialization for ‘comb_ab[1]’)

how to include memeber variable in static const * char array on gcc? please help me!

Answer 1

In C, initializers for objects of static storage duration must be constant expressions.

The value of a variable is never a constant expression, even if it is a const-qualified variable.

Therefore, you cannot use the value aas an initializer for comb_ab.

++ .

C, comb_ab main; main, "" comb_ab .

---

: const char * char *. , . g++, .

Answer 2

. C (C11, §6.6/9).

#include <stdio.h>

static const char *a = "this is a";
static const char *b = "this is b";

static const char **comb_ab[2] =
{
    &a,
    &b
};

int main()
{
    for (int i = 0; i < sizeof(comb_ab)/sizeof(comb_ab[0]); i++) {
        printf("%s\n", *comb_ab[i]);
    }
}

, a b . :

static const char *comb_ab[] =
{
    "this is a",
    "this is b",
};