Gerrit: is there a way to push only the top commit on the same branch?

Question

After searching for the light and searching for several similar questions, none of them seemed to really answer my question (below the list of related questions that I found).

I am developing further changes on top of a commit that have not yet been reviewed, but I want to save the changes separately. When I try to click a new patch for verification, I get an error message:

! [remote rejected] HEAD -> refs/for/master (no changes made)

Scenario: In my branch I have Commit A (merged) <- Commit B (cherry / not loaded) <- Commit C (with recent changes that I want to push).

As already mentioned, Commit C depends on B (but since I want them to be separated, squash cannot be done. Also, deleting B is not an option, as it adds changes that are not yet present, it is C).

So, when I try to press Commit C to view, I get the error message above (I understand that this is due to the fact that Commit B is under the new Commit C).

My question is: is there a way to send only Commit C to Gerrit before Commit B is merged? Or do I really have to wait until B is merged so that I can send Commit C up?

Homework:

Gerrit Workflow - Push a single commit to a thread thread

Git / gerrit, push remote rejected unchanged

Is there a way to force Gerrit to have all the commit in the branch to click on code view?

Git -

Answer 1

, commit-C unmerged commit-B, , commit-C commit-B '( , commit-B.

:

• -B ( Gerrit > > > ):

  git fetch https://USER@SERVER/a/REPO-PATH/REPO-NAME refs/changes/X/Y/Z && & & git checkout FETCH_HEAD

• commit-B

  git checkout -b some-branch

• commit-C change, commit Gerrit

, Gerrit commit-C commit-B . , - commit-B, commit-C, .

Answer 2

, (squash) , ( B), B , , .