How to start / stop python function from 10 to 12:30

Question

I am trying to create a function (for example, def startTime () :) that performs other functions, such as def runFunc (), which are launched every day when executed with a python script at 10 am and automatically stop (or script) at 12:30 Afternoon. like startTime (start_time, stop_time, runFunc)

Can someone help me? I am trying to schedule startTime from 10:00 to 12:30.

import threading
import schedule
import time

def runFunc(interval, innerFunc, iterations = 0):
   if iterations != 1:
      threading.Timer (interval,runFunc, [interval, innerFunc , 0 ]).start ()
   innerFunc ()

def A():
     print "Hello World- A"
def B():
     print "Hello World- B"

I tried, but did not work

def startTime(job):
      schedule.every().day.at("10:00").do(job)
      while True:
           schedule.run_pending()

startTime(runFunc(60,A))
startTime(runFunc(300,B))

runFunc (60, A) works fine, but cannot schedule runFunc from 10:00 to 12:30.

another way

from datetime import datetime, time
now = datetime.now()
now_time = now.time()
now_time
if time(5,27) <= now.time() <= time(5,28):
    runFunc(10,A)

runFunc really stops, it continues execution after time

Answer 1

, , script. , :

import threading
import schedule
import time
import datetime
import sys
def test():
    print('{} This is a test'.format(datetime.datetime.now())) #this works ok

def exit():
    print('{} Now the system will exit '.format(datetime.datetime.now())) #this works ok
    sys.exit()

schedule.every().day.at("09:57").do(test)
schedule.every().day.at('09:58').do(exit)

while True:
    schedule.run_pending()
    time.sleep(1)

" ", "exit", script.

, :

def test():
    while True: 
        print "This is a test"
        time.sleep(5)

script . , Python while test .

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, Python Schedule, .

" " Overflow, , Python 2.7:

import threading
    import schedule
    import time
    import datetime
    import sys

def doit(stop_event, arg):
    while not stop_event.wait(1): 
        #By wait(1) you repeat the loop every 1 sec. 
        #Applying wait(0) , loops run immediatelly until to be stopped by  stop_event
        print ("working on %s" % arg)
    print("Stopping as you wish.")


def startit():
    global pill2kill
    global t
    pill2kill = threading.Event()
    t = threading.Thread(target=doit, args=(pill2kill, "task"))
    t.start()

def stopit():
    global pill2kill
    global t
    pill2kill.set()
    t.join()

#startit() #Manual call for Testing 
#time.sleep(5) #Wait 5 seconds
#stopit() #Manual call for Testing

schedule.every().day.at("12:48").do(startit)
schedule.every().day.at('12:49').do(stopit)

#schedule.every().day.at("12:50").do(startit) #Uncomment this to recall it for testing
#schedule.every().day.at('12:51').do(stopit) #Unocmment this to recall it for testing

while 1:
    schedule.run_pending()
    time.sleep(1)

Python Crontab , .

PS: , Python Schedule Lib , script date.now() , , ​​ - (, Schedule Lib).
cron, script , datetime. /.

from datetime import datetime
import time

def test():
    global hasrun
    print('{} This is a test'.format(datetime.now()))
    time.sleep(5)
    hasrun=True

year,month,day,hour,minute=2016,12,23,15,55 
hasrun=False
now=datetime.now()

print "Now the time is :", now
jobstart=datetime(year,month,day,hour,minute)
jobstop=datetime(year,month, day,hour,minute+1)
print "Job will run at: ", jobstart
print "Job will finish at: ", jobstop
#print datetime.now() - jobstart
while True:
    while ((datetime.now() > jobstart) and (datetime.now() < jobstop )): 
        test()
    else:
        print('{} Please Wait...'.format(datetime.now()))
        if hasrun:
#           day=day+1
            minute=minute+2 #Just for Testing
            jobstart=datetime(year,month,day,hour,minute)
            jobstop=datetime(year,month, day,hour,minute+1)
            print "the job will run again ", jobstart
            print "and will finish at ", jobstop
            hasrun=False
        time.sleep(5)