Node - Wait for the loop to complete?

Question

When the function below ends and provides the final list of elements in the albums of the array, I want it to call another function / do something else with the list.

He is currently publishing [] before the function exits, and I know that it is due to asynchronous execution, but I thought Node is read linearly, since is it single-threaded?

function getAlbumsTotal(list, params){
    for(var i = 0; i<list.length; i++){
        api.getArtistAlbums(list[i], params).then(function(data) {
            for(var alb = 0; alb<data.body.items.length; alb++){
                albums.push(data.body.items[alb].id);
            }
        }, function(err) {
            console.error(err);
        });
    }
    console.log(albums);
    //do something with the finalized list of albums here
}

Answer 1

, then, , , , console.log.

:

function getAlbumsTotal(list, params){
    var promises = list.map(function (item) { // return array of promises
        // return the promise:
        return api.getArtistAlbums(item, params)
            .then(function(data) {
                for(var alb = 0; alb<data.body.items.length; alb++){
                    albums.push(data.body.items[alb].id);
                }
            }, function(err) {
                console.error(err);
            });
    });
    Promise.all(promises).then(function () {
        console.log(albums);
        //do something with the finalized list of albums here
    });
}

NB: - albums . . , , Promise.all . :

function getAlbumsTotal(list, params){
    var promises = list.map(function (item) { // return array of promises
        // return the promise:
        return api.getArtistAlbums(item, params)
            .then(function(data) {
                // return the array of album IDs:
                return Array.from(data.body.items, function (alb) {
                    return alb.id;
                });
            }, function(err) {
                console.error(err);
            });
    });
    Promise.all(promises).then(function (albums) { // albums is 2D array
        albums = [].concat.apply([], albums); // flatten the array
        console.log(albums);
        //do something with the finalized list of albums here
    });
}

Answer 2

, node.js, , , . " " , .

, runnable , , , . , , , , , .

function getArtistAlbums(artist, params){
  var artistAlbums = {
    'Aphex Twin':['Syro', 'Drukqs'],
    'Metallica':['Kill \'Em All', 'Reload']
  };
  return new Promise(function (fulfill, reject){
    fulfill(artistAlbums[artist]);
  });

}
function getAlbumsTotal(list, params){
  var listCount = 0;
  for(var i = 0; i<list.length; i++){
    getArtistAlbums(list[i], params)
      .then(function(data) {
        listCount++;
        for(var alb = 0; alb<data.length; alb++){
        //for(var alb = 0; alb<data.items.length; alb++){
          //albums.push(data.body.items[alb].id);
          albums.push(data[alb]);
        }
        // print out album list at the end of our loop
        if(listCount == list.length){
          console.log(albums);
        }

      }, function(err) {
        console.error(err);
      });
  }
  // prints out too early because of async nature of node.js
  //console.log(albums);
}

var listOfArtists = ['Aphex Twin', 'Metallica'];
var albums = [];

getAlbumsTotal(listOfArtists, 'dummy params');