Upload StorageFile to PHP File

Question

I am trying to load a StorageFile (mainly image files) into a PHP file so that it can save it to the server.

ViewModel.cs

public async Task<bool> uploadFile(StorageFile file)
{
    try
    {
        using (HttpMultipartFormDataContent form = new HttpMultipartFormDataContent())
            {
                using (IInputStream fileStream = await file.OpenSequentialReadAsync())
                {
                    HttpStreamContent streamContent = new HttpStreamContent(fileStream);
                    form.Add(streamContent, "file", file.Name);

                    using (HttpClient client = new HttpClient())
                    {
                        using (HttpRequestMessage request = new HttpRequestMessage(HttpMethod.Post, new Uri("localhost/uploadFile.php")))
                        {
                            request.Content = form;
                            HttpResponseMessage response =  await client.SendRequestAsync(request);
                            Debug.WriteLine("\nRequest: " + request.ToString());
                            Debug.WriteLine("\n\nResponse: " + response.ToString());
                        }
                    }
                }
            }
            return true;
   }
   catch (Exception e)
   {
       Debug.WriteLine(e.Message);
       return false;
   }
}

uploadFile.php

<?php
$uploaddir = 'uploads/';
$uploadedFile = $uploaddir . basename($_FILES['file']['name']);

if (move_uploaded_file($_FILES['file']['tmp_name'], $uploadedFile)){
    echo 'File upload success!';
} else {
    echo 'Possible file upload attack!';
}
?>

The problem is that when I try to download the file, it gave me an error The object has been closed. (Exception from HRESULT: 0X80000013)and Exception thrown: 'System.ObjectDisposedException' in mscorlib.ni.dll.. I don’t understand, I upload the file inside the instruction using, how can this be located? Am I doing something wrong?

Debugging shows me this

: : POST, RequestUri: 'http://localhost/uploadFile.php', : Windows.Web.Http.HttpMultipartFormDataContent, TransportInformation: ServerCertificate: '', ServerCertificateErrorSeverity: None, ServerCertificateErrors: {}, ServerIntermediateCertificates: {}, : {Accept-Encoding: gzip, deflate} {Content-Length: 27749, Content-Type: multipart/form-data; border = 9955f08b-e82d-428b-82e1-3197e5011ccd}

: StatusCode: 200, ReasonPhrase: 'OK', : 2, : Windows.Web.Http.HttpStreamContent, : {: Keep-Alive, : Apache/2.4.18 (Ubuntu), Keep -Alive: timeout = 5, max = 100, Date: Sun, 06 Nov 2016 04:02:40 GMT} {Content-Length: 28, Content-Type: text/html; = UTF-8}

Answer 1

, IDisposable. , Dispose(). , :

 HttpMultipartFormDataContent form = new HttpMultipartFormDataContent();               
 IInputStream fileStream = await file.OpenSequentialReadAsync();
 HttpStreamContent streamContent = new HttpStreamContent(fileStream);
 form.Add(streamContent, "file", file.Name);    
 HttpClient client = new HttpClient();             
 HttpRequestMessage request = new HttpRequestMessage(HttpMethod.Post, new Uri("http://127.0.0.1:9096/hello.php"));
 request.Content = form;      
 HttpResponseMessage response = await client.SendRequestAsync(request);
 Debug.WriteLine("\nRequest: " + request.ToString());
 Debug.WriteLine("\n\nResponse: " + response.ToString());
 request.Dispose();
 client.Dispose();
 fileStream.Dispose();
 form.Dispose();

form.Dispose();. , HttpMultipartFormDataContent.Add . , , , HttpMultipartFormDataContent, ReadAsBufferAsync, , .

, closed:

HttpMultipartFormDataContent form = new HttpMultipartFormDataContent();
using (IInputStream fileStream = await file.OpenSequentialReadAsync())
{
    HttpStreamContent streamContent = new HttpStreamContent(fileStream);
    form.Add(streamContent, "file", file.Name);

    using (HttpClient client = new HttpClient())
    {
        using (HttpRequestMessage request = new HttpRequestMessage(HttpMethod.Post, new Uri("http://127.0.0.1:9096/hello.php")))
        {
            request.Content = form;
            HttpResponseMessage response = await client.SendRequestAsync(request);
            Debug.WriteLine("\nRequest: " + request.ToString());
            Debug.WriteLine("\n\nResponse: " + response.ToString());
        }
    }
}