Python Time Function Mismatch

Question

I was given the task: I needed to create two small functions that give equal chances to “heads” or “tails” and, similarly to 6 dice, 1,2,3,4, 5 or 6.

Important: I could not use randint or similar functions for this purpose.

So, I created those two functions that generate a "pseudo-random number" using the time function (the first digit of milliseconds) from the python library:

import time

def dice():
    ctrl = False
    while ctrl == False:
            m = lambda: int(round(time.time() * 1000))
            f = m()
            d = abs(f) % 10
            if d in range(1,7):
                    return d
                    ctrl = True


def coin():
        m = lambda: int(round(time.time() * 1000))
        f = m()
        if f % 2 == 0:
                return "Tails"
        elif f == 0:
                return "Tails"
        else:
                return "Heads" (EDIT: I don't know why i typed "Dimes" before)

However, I observed a tendency to give “Tails” over “Heads”, so I created a function to check the percentage of “Tails” and “Heads” in 100 throws:

def _test():
    ta = 0
    he = 0
    x = 100
    while x > 0:
        c = coin()
        if c == "Tails":
            ta += 1
        else:
            he += 1
    x -= 1
    time.sleep(0.001)
print("Tails:%s Heads:%s" % (ta, he))

The test result was (several times):

Tails:56 Heads:44

So, I did the same with the cubes function, and the result was:

1:20 2:20 3:10 4:20 5:10 6:20

, , - - - - - "3" "5" (, , ), , "0" "7".

.

EDIT:

round() m = lambda: int(round(time.time() * 1000)) - .

Answer 1

round , , , , (.. "" - ).

:

, round(), 10 ndigits; , (, , round(0.5), round(-0.5) 0, round(1.5) 2).

, ; , :

>>> [dice() for x in range(11)]
[5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5]
>>> [coin() for x in range(11)]
['Dimes', 'Dimes', 'Dimes', 'Dimes', 'Dimes', 'Dimes', 'Dimes', 'Dimes', 'Dimes', 'Dimes', 'Dimes']

, , - , , . , , , , , .