Regular Expression Capture Group

Question

I have a method for finding regular expressions in a string:

extension String {
    func searchRegex (regex: String) -> Array<String> {
        do {
            let regex = try NSRegularExpression(pattern: regex, options: NSRegularExpressionOptions(rawValue: 0))
            let nsstr = self as NSString
            let all = NSRange(location: 0, length: nsstr.length)
            var matches : Array<String> = Array<String>()
            regex.enumerateMatchesInString(self, options: NSMatchingOptions(rawValue: 0), range: all) {
                (result : NSTextCheckingResult?, _, _) in
                let theResult = nsstr.substringWithRange(result!.range)
                matches.append(theResult)
            }
            return matches
        } catch {
            return Array<String>()
        }
    }
}

It works well. But if I have a regex product_title:\['(.*)', it returns me product_title:[\'Some title bla bla\', but I only need a part (.*).

I am new to swift, but in python this problem is solved using a function groups(). How to use capture group in swift. Please provide an example.

Answer 1

NSTextCheckingResult numberOfRanges rangeAtIndex(), . , , , :

        var matches : Array<String> = Array<String>()
        regex.enumerateMatchesInString(self, options: NSMatchingOptions(rawValue: 0), range: all) {(result : NSTextCheckingResult?, _, _) in
            let capturedRange = result!.rangeAtIndex(1)
            if !NSEqualRanges(capturedRange, NSMakeRange(NSNotFound, 0)) {
                let theResult = nsstr.substringWithRange(result!.rangeAtIndex(1))
                matches.append(theResult)
            }
        }