Drop inbound nodes in a directed graph

I would like to drop incoming nodes in a directed graph.

tl; dr (go to section 3)

I have a graph in which I run BFS to remove all unrelated nodes (relative to the candidate edge).

1. Example chart data

Let it be the graph data structure:

Where: - id1- source, id2- target

      var links = [
        {id1: 1, id2: 2},
        {id1: 2, id2: 3},
        {id1: 9, id2: 3},
        {id1: 6, id2: 8},
        {id1: 3, id2: 4}
      ]

Visualization above:

Graphic visualization for the above structure

2. I successfully remove unbound nodes / edges

I run BFS (function below) to drop all unrelated nodes relatively edge=1that give this:

      var links = [
        {id1: 1, id2: 2},
        {id1: 2, id2: 3},
        {id1: 9, id2: 3},
       // {id1: 6, id2: 8}, Discarded (no connection with 1)
        {id1: 3, id2: 4}
      ]

Visualization for the above:

Graphic visualization for the above structure

3. Now I want to delete incoming nodes

, "" node (- ), edge=1

:

      var links = [
        {id1: 1, id2: 2},
        {id1: 2, id2: 3},
        {id1: 9, id2: 3}, // remove this
        {id1: 3, id2: 4}
      ]

Graphic visualization of the desired result showing the cut link

?

/:

var filterUnrelated = function(data, candidateId) {
  var toTest = [candidateId];
  var connected = [];

  function addToTest(node) {
    //If the node is not already set to be tested, and have not been tested
    if (connected.indexOf(node) < 0 && toTest.indexOf(node) < 0) {
      toTest.push(node);
    }
  }

  function findAllConnectedNode(node) {
    //We only test connected node, so this node should be connected
    connected.push(node);
    //Find every link with that node
    data.filter(function(d) {
      return (d.id1 === node) || (d.id2 === node);
      //Add the linked node to test
    }).map(function(d) {
      if (d.id1 === node) {
        addToTest(d.id2);
      }
      else { //d.id1 === node
        addToTest(d.id1);
      }
    });
  }

  while (toTest.length > 0) {
    findAllConnectedNode(toTest.shift());
  }

  return data.filter(function(d) {
    return (connected.indexOf(d.id1) >= 0 ||
      connected.indexOf(d.id2) >= 0);
  })
}


var links = [
  {id1: 1, id2: 2},
  {id1: 2, id2: 3},
  {id1: 9, id2: 3},
  {id1: 6, id2: 8},
  {id1: 3, id2: 4}
]

console.log(filterUnrelated(links, 1));
          
Hide result
+4
1

, (.. node, ), node node.

function removeIncoming(data, source){
    // keep track of the member we are looking for
    var target = source;
    // the resulting graph
    var result = [];
    // iterate through the data, looking for the target
    for(var i = 0; i < data.length; i++){
        // the object in the list
        var piece = data[i];
        // its properties id1 and id2
        var id1 = piece.id1;
        var id2 = piece.id2;

        // when we have found what we are looking for
        if(id1 === target){
            // look for its child
            target = id2;
            // start at the beginning
            i = -1;
            // and add the link to the resulting list
            result.push(piece);
        }
    }

    return result;
}

, , indexOf .

function removeIncoming(data, source){
    // copy the data
    var dataCopy = Array.prototype.slice.call(data);
    // keep track of the members we are looking for
    var targets = [source];
    // the resulting graph
    var result = [];
    // iterate through the data, looking for the target
    for(var i = 0; i < dataCopy.length; i++){
        // the object in the list
        var piece = dataCopy[i];
        // its properties id1 and id2
        var id1 = piece.id1;
        var id2 = piece.id2;

        // when we have found what we are looking for
        if(targets.indexOf(id1) >= 0){
            // begin looking for its child
            targets.push(id2);
            // remove the node we just looked at
            dataCopy.splice(i, 1);
            // start at the beginning
            i = -1;
            // and add the link to the resulting list
            result.push(piece);
        }
    }

    return result;
}
+2

Source: https://habr.com/ru/post/1656291/


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