SimpleDateFormat with template yyyyMMddhhmmss, unable to parse date "20160327020727"

Question

I get an exception when parsing a date 20160327020727with a format yyyyMMddhhmmss. Note that the softness parameter is set to false.

    SimpleDateFormat df = new SimpleDateFormat("yyyyMMddhhmmss");
    df.setLenient(false);
    try {
        Date dt = df.parse("20160327020727");
    } catch (ParseException e) {
        e.printStackTrace();
    }

It processes other dates in the same format and works as expected. Why is this happening?

Answer 1

CET changes to summer time on the last Sunday of March, so there is no 2AM on this day.

You go from 1:59 to 3:00

Answer 2

You get an error because this time does not exist in your default time zone.

UTC, df.setTimeZone(TimeZone.getTimeZone("UTC"));

CET → No 2AM .

Answer 3

Change it to "yyyyMMdd HHmmss"so you can easily disassemble it.