How to perform several tasks in parallel?

I attend the Parallel Programming class and it shows a parallel interface:

def parallel[A, B](taskA: => A, taskB: => B): (A, B) = {
  val ta = taskA
  val tb = task {taskB}
  (ta, tb.join())
}

and the following is not true:

def parallel[A, B](taskA: => A, taskB: => B): (A, B) = {
  val ta = taskB
  val tb = task {taskB}.join()
  (ta, tb)
}

see interface more https://gist.github.com/ChenZhongPu/fe389d30626626294306264a148bd2aa

He also shows us the correct way to complete four tasks:

def parallel[A, B, C, D](taskA: => A, taskB: => B, taskC: => C, taskD: => D): (A, B, C, D) = {
    val ta = task { taskA }
    val tb = task { taskB }
    val tc = task { taskC }
    val td = taskD
    (ta.join(), tb.join(), tc.join(), td)
}

My question is: if I do not know the number of tasks (task list), how can I correctly call joinfor each task?

tasks.map(_.join()) // wrong

Edit

A similar discussion also takes place in the Discuss this week module: Parallel Programming

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3 answers

:

def parallel[A](tasks: (() => A)*): Seq[A] = {
  if (tasks.isEmpty) Nil
  else {
    val pendingTasks = tasks.tail.map(t => task { t() })
    tasks.head() +: pendingTasks.map(_.join())
  }
}

( , by-name - )

:

object ParallelUsage {
  def main(args: Array[String]) {
    val start = System.currentTimeMillis()

    // Use a list of tasks:
    val tasks = List(longTask _, longTask _, longTask _, longTask _)
    val results = parallel(tasks: _*)
    println(results)

    // or pass any number of individual tasks directly:
    println(parallel(longTask, longTask, longTask))
    println(parallel(longTask, longTask))
    println(parallel(longTask))
    println(parallel())

    println(s"Done in ${ System.currentTimeMillis() - start } ms")
  }

  def longTask() = {
    println("starting longTask execution")
    Thread.sleep(1000)
    42 + Math.random
  }
}

Scala

, :

val tasks = Vector(longTask _, longTask _, longTask _)
val results = tasks.par.map(_()).seq
+2

Future.sequence . Task, Monad, .

  /** Transforms a `TraversableOnce[Task[A]]` into a `Task[TraversableOnce[A]]`.
   *  Useful for reducing many `Task`s into a single `Task`.
   */
  def parallel[
    A,
    M[X] <: TraversableOnce[X]
  ](in: M[Task[A]])(
    implicit cbf: CanBuildFrom[M[Task[A]], A, M[A]],
    executor: ExecutionContext
  ): Task[M[A]] = {
    in.foldLeft(Task.point(cbf(in))) {
      (fr, fa) => for (r <- fr; a <- fa) yield (r += a)
    }.map(_.result())(executor)
  }

Scala, , Task map flatMap, , , implicit builder , Scala.

0

parallel(), , Future. , Javascript Promises:

import scala.concurrent.{Await,Future}
import scala.concurrent.duration.Duration
import scala.concurrent.ExecutionContext.Implicits.global

def parallel[A, B](taskA: =>A, taskB: =>B): (A,B) = {
  val fB:Future[B] = Future { taskB }
  val a:A = taskA
  val b:B = Await.result(fB, Duration.Inf)
  (a,b)
}

taskB taskA . taskA , , fB. , , .

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Source: https://habr.com/ru/post/1649852/


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