It seems to scalazprovide an instance Functorfor List, but does not provide it for Array(or Seq).
scalaz
Functor
List
Array
Seq
scala> val fa = Functor[Array] <console>:17: error: could not find implicit value for parameter F: scalaz.Functor[Array] val fa = Functor[Array] ^ scala> val fl = Functor[List] fl: scalaz.Functor[List] = scalaz.std.ListInstances$$anon$1@20c4b59 scala> val fl = Functor[Seq] <console>:17: error: could not find implicit value for parameter F: scalaz.Functor[Seq] val fl = Functor[Seq] ^
Why? Are they functors?
Scala , Functor s. " " . , Array , Functor . Seq, , , , "" . , Seq , , , - ?
Source: https://habr.com/ru/post/1649803/More articles:2 ways to access the value of an array of pointers in C - cAttributeError: the 'Figure' object does not have the 'plot' attribute - pythonUser user model with Django CMS. Cannot resolve bases for cms.PageUser - djangoIntellij Idea alt + click to evaluate the code of a debugger not working in the mint - intellij-ideaScalable architecture for socket.io - node.jsЛаравельский кеш-путь?! Никогда не видел - laravelWhat is a dependency injection container? - oopWhen dependency injection containers get too big, and what can I do about it? - oopCSS shifted from transition does not work - htmlПодготовленное выражение SQL Studio - sql-serverAll Articles