The short answer is no.
Long answer:
You can do this by using finditer
to view all matches, and then manually match the examples.
tests = (
"11foo11",
"22Foo22",
"33foO33",
"44FOO44",
)
import re
foobar = "(?i)(foo)"
for teststr in tests:
replstr = "bar"
newchars = list(teststr)
for m in re.finditer(foobar, teststr):
mtext = m.group(1)
replchars = list(replstr)
for i, ch in enumerate(mtext):
if ch.isupper():
replchars[i] = replchars[i].upper()
newchars[m.start():m.end()] = replchars
print("Old: ", teststr, " New: ", ''.join(newchars))