I have a REST API in java that accepts an image file and stores it on the server. I want to return the path to this loaded image in XML form, but I donβt know how to do it. Currently, it returns the response as a string in the browser.
Here is my code.
package com.javacodegeeks.enterprise.rest.jersey;
import java.io.File;
import java.io.FileOutputStream;
import java.io.IOException;
import java.io.InputStream;
import java.io.OutputStream;
import javax.ws.rs.Consumes;
import javax.ws.rs.POST;
import javax.ws.rs.Path;
import javax.ws.rs.core.MediaType;
import javax.ws.rs.core.Response;
import com.sun.jersey.core.header.FormDataContentDisposition;
import com.sun.jersey.multipart.FormDataParam;
@Path("/files")
public class JerseyFileUpload {
private static final String SERVER_UPLOAD_LOCATION_FOLDER = "/home/hassan/Downloads/";
@POST
@Path("/upload")
@Consumes(MediaType.MULTIPART_FORM_DATA)
public Response uploadFile(
@FormDataParam("file") InputStream fileInputStream,
@FormDataParam("file") FormDataContentDisposition contentDispositionHeader) {
String filePath = SERVER_UPLOAD_LOCATION_FOLDER + contentDispositionHeader.getFileName();
saveFile(fileInputStream, filePath);
String output = "File saved to server location : " + filePath;
return Response.status(200).entity(output).build();
}
private void saveFile(InputStream uploadedInputStream,
String serverLocation) {
try {
OutputStream outpuStream = new FileOutputStream(new File(serverLocation));
int read = 0;
byte[] bytes = new byte[1024];
outpuStream = new FileOutputStream(new File(serverLocation));
while ((read = uploadedInputStream.read(bytes)) != -1) {
outpuStream.write(bytes, 0, read);
}
outpuStream.flush();
outpuStream.close();
} catch (IOException e) {
e.printStackTrace();
}
}
}
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