This sample code from the Mozilla JS link uses the → and →> operators with the RHS 0 argument. I assume this is an alternative to Math.floor (), which has a performance advantage because instead of the built-in operator, you need to look for a function instead. But what difference does → vs →> make with zero shift?
From MDN Article :
>>is the Sign-shift to the right of the shift :
>>
Shifts a in binary representation b (<32) bits to the right, discarding bits shifted from.
>>>is the Zero Zero Shift :
>>>
a b (< 32) , , , .
, , .
fooobar.com/questions/1179/... :
, , 0 → 0, 32- int. , triple → > Number , , , 32- . → > 0 , 0 0xFFFFFFFF.
, 32- int. , , (typeof number) floored int, 32- , JS- :)
- vs .
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