How to send a method name as a parameter

Question

I want to create some engine for monogame in C #. My engine should include a button. I want to do this with events. Basically, I did it, but I want to improve it, and my problems started.

  class Button : Component
  {
    ....
    public event EventHandler<EventArgs> Click;
    public void OnClick()
    {
        if (MousePressed() && Click != null)
        {
            Click(this, new EventArgs());
        }
    }
  }

and when I want to add a Click event, I have to do it in another class:

_buttnon.Click += new EventHandler<EventArgs>(Method);
_buttnon.OnClick();

This works well, but I want to do it like this:

_button.RegisterClickEvent(Method);

so I added Button class code below:

 public void RegisterClickEvent(XXX method) {
        Click += new EventHandler<EventArgs>(method);
 }

I absolutely do not know that I need to replace XXX. I tried:

 public void RegisterClickEvent(void(object, EventArgs)method) {
        Click += new EventHandler<EventArgs>(method);
 }

but it does not work. I tried to find something on Google, but I don't know what I'm looking for.

Answer 1

Simple delegate use:

  public void RegisterClickEvent(EventHandler<EventArgs> method)
  {
    Click += new EventHandler<EventArgs>(method);
  }

or

  public void RegisterClickEvent(EventHandler method)
  {
    Click += new EventHandler<EventArgs>(method);
  }

( , VS2015, , ( 2010 , ).

Answer 2

, , - :

public void RegisterClickEvent(Action<object, EventArgs> method) 
{
    Click += new EventHandler<EventArgs>(method);
}

Answer 3

- EventHandler<EventArgs> get EventHandler<EventArgs> :

public void RegisterClickEvent(EventHandler<EventArgs> method)
{
    Click += new EventHandler<EventArgs>(method);
}

...
RegisterClickEvent(Method);

Answer 4

Method - . , . , , .

,

public void RegisterClickEvent(EventHandler<EventArgs> handler) 
{
    Click += handler;
}

Method EventHandler<EventArgs>,

_button.RegisterClickEvent(Method);

_button.RegisterClickEvent(new EventHandler<EventArgs>(Method));

+= .