Sort an XML file using XMLElement InnerText

Question

Please look at the XML file. I want to sort the XML file by tag<Order>

<MyRootNode>
  <Tab>
    <Name>ABC</Name>
    <Order>200</Order>
  </Tab>
  <Tab>
    <Name>MNO</Name>
    <Order>100</Order>
  </Tab>
  <Tab>
    <Name>XYZ</Name>
    <Order>90</Order>
  </Tab>
  <Tab>
    <Name>QWE</Name>
    <Order>40</Order>
  </Tab>
  <Tab>
    <Name>KML</Name>
    <Order>20</Order>
  </Tab>
</MyRootNode>

So the answer will be as follows.

<MyRootNode>
  <Tab>
    <Name>KML</Name>
    <Order>20</Order>
  </Tab>
  <Tab>
    <Name>QWE</Name>
    <Order>40</Order>
  </Tab>
  <Tab>
    <Name>XYZ</Name>
    <Order>90</Order>
  </Tab>
  <Tab>
    <Name>MNO</Name>
    <Order>100</Order>
  </Tab>
  <Tab>
    <Name>ABC</Name>
    <Order>200</Order>
  </Tab>
</MyRootNode>

How can I do this in C # 3.5?

Answer 1

You tried,

XElement root = XElement.Load(xmlfile);
var orderedtabs = root.Elements("Tab")
                      .OrderBy(xtab => (int)xtab.Element("Order"))
                      .ToArray();
root.RemoveAll();
foreach(XElement tab in orderedtabs)
    root.Add(tab);
root.Save(xmlfile);

Answer 2

use XSLT

eg:

dataSort.xslt:

<?xml version="1.0" encoding="UTF-8"?> 
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes" />
<xsl:template match="/">
    <xsl:element name="MyRootNode">
        <xsl:apply-templates select="MyRootNode" />
    </xsl:element>
</xsl:template>

<xsl:template match="MyRootNode">
    <xsl:for-each select="Tab">
        <xsl:sort select="Order/text()" data-type="number"/>
            <xsl:copy-of select="." />
    </xsl:for-each>
</xsl:template>
</xsl:stylesheet>

Sample.cs:

//convert data.xml to sortedData.xml

using System;
using System.Xml.Xsl;

class Sample {
    static public void Main(){
        XslCompiledTransform xslt = new XslCompiledTransform();
        xslt.Load("dataSort.xslt");
        xslt.Transform("data.xml", "sortedData.xml");
    }
}

Answer 3

, XML , , XML .

Answer 4

System.Xml.Linq;

xlements,

var xnodes = oldXDoc.Element("MyRootNode").Elements();
var sortedXNodes = xnodes.OrderBy(node => Convert.ToInt32( node.Element("Order").Value));
var newXdoc = new XDocument(new XElement("MyRootNode", sortedXNodes));