How to display the data of another table as a grid in yii2?

Question

In siteControllerI am writing an array of queries from dataProviderto index.phpto display in table form. In index.phpI want to display member nameinstead memberID. To do this, I am writing an internal query and successfully running on the command line successfully. I can't print first nameinstead. ' member id'

      public function actionIndex()
      {              
     $query = new \yii\db\Query;
      $query->select(['member.firstName',
                    'complaint.practiceCode','complaint.id',
                    'complaint.description','member.firstName'])
           ->from(['complaint'])
           ->innerJoin(['member','complaint.memberID = member.id'])
           ->groupBy(['complaint.id'])
           ->where(['complaint.deleted' => 'N']);
     $query->createCommand();

Here I have the pass data when creating $dataProvider4, but I cannot set the value firstNameinstead memberID.

      $dataProvider4= new ActiveDataProvider([
            'query' => $query,
            'pagination' => false,
       ]);

        return $this->render('index', [
       'dataProvider4'=>$dataProvider4]);

<?= GridView::widget([
    'dataProvider'=>$dataProvider4,
    'summary'=>'Total'.'&nbsp<b>'.$complaintModel.'</b>&nbsp'.'Complaints',
    'columns' => [
       ['class' => 'yii\grid\SerialColumn'],
           'practiceCode',
            // 'memberID',
            'description',
            'status',
       ],
    ]); ?>

I have transfer data through dataProvider.

Answer 1

, , . , Yii. .

public function actionIndex()
    {              
    $query = Member::find()->
        ->select(['firstName', complaint.practiceCode', complaint.id', 'complaint.description'])
        ->groupBy(['complaint.id'])
        ->joinWith('complaints')//Tells Yii to use the complains relation that we define below. By default it is an inner join
        ->where(['complaint.deleted' => 'N']);

$dataProvider= new ActiveDataProvider([
    'query' => $query,
    'pagination' => false,
]);

return $this->render('index', [
    'dataProvider4'=>$dataProvider]);

, ;

public function getComplaints(){
    return $this->hasMany(Complaints::className(), 'memberID' => 'id');
}

, , .

Yii .

Answer 2

dataProvider,

, , dataprovider, . , , ;

<?= GridView::widget([
        'dataProvider' => $dataProvider4,
        //'summary'=>'Total'.'&nbsp<b>'.$complaintModel.'</b>&nbsp'.'Complaints',
        'columns' => [
           ['class' => 'yii\grid\SerialColumn'],
           'practiceCode',
          /* ['attribute' => '',
            'value' => function ($model) {
               $myMemberModel =  Member::find()->
                       where(['id'=> $model->memberID ])->one();
               if (isset($myMemberModel) {
                  return $myMemberModel->firtsName;
               } else {
                 return ' id : '.  $model->memberID . ' do not match ';
               }
             }],*/
              'firstName',
               'memberID',
              'description',
              'status',
              ],
         ]); 
?>