Reordering legend colors in matte strip

Question

Trying to change some properties associated with a row in a matrix is ​​very confusing. I found several solutions for my problems here. However, there is one that I cannot find. Consider the following:

ax1 = subplot(121);
id2 = [8;2;3;5];
id2_t = sum(id2);
id3 = (id2/id2_t).*100; id3(:,2) = 0;
H1 = bar(id3','stacked','EdgeColor','none');
set(gca,'XTicklabel',[]);
xlim([0.75 1.25]);

% add legend
str = {'str1','str2','str3','str4'};
ll = legend(str);
legend('boxoff');
set(ll,'PlotBoxAspectRatio',[0.5 1 1]);
ll_i = get(ll,'position');
set(ll, 'Position', [0.25 ll_i(2)-0.1 ll_i(3) ll_i(4)]);

% change dimensions of plot
AX1 = get(ax1,'position');
set(ax1,'position',[AX1(1) AX1(2) AX1(3)/2.7 AX1(4)]);

This code was written to create a single stack bar in Matlab, and not one of the most complex solutions, but it works. Below is a bar chart:

Now I am trying to reorder my records in the legend to fit the plot. Some people suggested flipud or fliplr on strings, but this does not work. This changes the sequence of lines, but does not change colors. Can someone suggest a method that matches the ordering of colors between the legend and the plot? For example, str4 should be blue

, flipud , . :

x = 1:10;
h = zeros(5, 1);
hold on;
cols = {'r', 'g', 'b', 'y', 'k'};
for k = 1:5
    h(k) = plot(x, k*x, cols{k});
end
legend({'one','two','three', 'four', 'five'}) % one way
legend(flipud(h), {'one', 'two', 'three', 'four', 'five'}) % another way

, , :

ax1 = subplot(121);
id2 = [8;2;3;5];
id2_t = sum(id2);
id3 = (id2/id2_t).*100; id3(:,2) = 0;
H1 = bar(id3','stacked','EdgeColor','none');
set(gca,'XTicklabel',[]);
xlim([0.75 1.25]);

% add legend
str = {'str1','str2','str3','str4'};
[ll ll2]= legend(str);
legend('boxoff');
set(ll,'PlotBoxAspectRatio',[0.5 1 1]);
ll_i = get(ll,'position');
set(ll, 'Position', [0.25 ll_i(2)-0.1 ll_i(3) ll_i(4)]);

% change dimensions of plot
AX1 = get(ax1,'position');
set(ax1,'position',[AX1(1) AX1(2) AX1(3)/2.7 AX1(4)]);

map = colormap;
n = size(ll2,1);
MAP = map(linspace(size(map,1),1,n/2),:); %// n is as my code above
for k = (n/2 + 1):n;
    a1 = get(ll2(k),'Children');
    set(a1,'FaceColor',MAP(k-n/2,:));
end

Answer 1

, ( , , ):

[ll, ll2] = legend(str);

n = size(ll2,1);
for k = (n/2 + 1):n
    ll2(k).Children.FaceColor = RGBTriple;
end

, RGBTriple [1,0,0], , . , (, ) .

, :

• :

  map  = colormap;
  

• :

  MAP = map(linspace(size(map,1),1,n/2),:); %// n is as my code above
  

• RGBTriple:

  for k = (n/2 + 1):n
      ll2(k).Children.FaceColor = MAP(k-n/2,:);
  end