Sort items in a specific order in python

How can I sort it custom?

Input:

[
    {value: "typeA"},
    {value: "typeC"},
    {value: "typeB"},
    {value: "typeC"},
    {value: "typeB"},
    {value: "typeA"}
]

Expect the result:

[
    {value: "typeB"},
    {value: "typeB"},
    {value: "typeC"},
    {value: "typeC"},
    {value: "typeA"},
    {value: "typeA"}
]

my_own_order = ['typeB', 'typeC', 'typeA']

My python code is as below:

result = sorted(input, key=lambda v:v['value'])
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2 answers
>>> lst = [
...     {'value': "typeA"},
...     {'value': "typeC"},
...     {'value': "typeB"},
...     {'value': "typeC"},
...     {'value': "typeB"},
...     {'value': "typeA"}
... ]
>>> my_own_order = ['typeB', 'typeC', 'typeA']

Make comparison between typeB, typeC, typeAto 0, 1, 2

>>> order = {key: i for i, key in enumerate(my_own_order)}
>>> order
{'typeA': 2, 'typeC': 1, 'typeB': 0}

And use collation to sort:

>>> sorted(lst, key=lambda d: order[d['value']])
[{'value': 'typeB'},
 {'value': 'typeB'},
 {'value': 'typeC'},
 {'value': 'typeC'},
 {'value': 'typeA'},
 {'value': 'typeA'}]
+8
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Try the following:

sorted(input, key=lambda v: my_own_order.index(v['value']))
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Source: https://habr.com/ru/post/1620307/


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