IOS 9 how to programmatically use the "Back to" function

Are there any api for calling the "Return to" programs programmatically to return to the application that called (openurl) mine?

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Unable to redirect back to application

Cause

The only possible way to launch another application programmatically (Exposed by Apple) is through URLScheme. This means that the current application must know the URL scheme for launching the application. In your case, the running application does not know the URL scheme of the running application. Thus, there is no way to return to the previous application.

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Source: https://habr.com/ru/post/1615940/


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