Why does the memory address contained in the pointer and the address of the pointer come out the same?

Question

Pointer variables simply point to other variable addresses in memory. And pointer variables have their own address in memory.

However, this code gives the same memory address for both.

int num=10;
int *ptr=#
printf("Address of variable num: %p\n",ptr);
printf("Address of pointer ptr: %d\n",&ptr);

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If you print both of them at the same time, then it works as expected.

Num variable address: 0028FF3C

Ptr Pointer Address: 0028FF38

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But if I print them one at a time, then it gives the same address for both.

printf("Address of variable num: %p\n",ptr);
//printf("Address of pointer ptr: %d\n",&ptr);

Variable num address: 0028FF38

//printf("Address of variable num: %p\n",ptr);
printf("Address of pointer ptr: %d\n",&ptr);

Ptr Pointer Address: 0028FF38

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I am using the mingw compiler on a windows 7 machine.

Answer 1

The compiler should only ensure that the variable is retained as long as it is used.

int a = 5;
int b = 7;
printf( "a * 5 = %d\n", a * 5); /* after this point, a is no longer needed */
printf( "b * 9 = %d\n", b * 9); /* after this point, b is no longer needed */

, b , , .

, , 25 63 a b.

Answer 2

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