Switch between different programs using scipy ode

I have a solver that can exchange between scipy.integrate.odeand scipy.integrate.odeint. Here is the code.

def f(y,s,C,u,v):
    y0 = y[0] # u
    y1 = y[1] # u'
    y2 = y[2] # v
    y3 = y[3] # v'
    dy = np.zeros_like(y)
    dy[0] = y1
    dy[2] = y3

    C = C.subs({u:y0,v:y2})
    dy[1] = -C[0,0][0]*dy[0]**2\
            -2*C[0,0][1]*dy[0]*dy[2]\
            -C[0,1][1]*dy[2]**2
    dy[3] = -C[1,0][0]*dy[0]**2\
            -2*C[1,0][1]*dy[0]*dy[2]\
            -C[1,1][1]*dy[2]**2
    return dy

def solve(C,u0,s0,s1,ds,solver=None):
    from sympy.abc import u,v
    if solver == None: # use lsoda from scipy.integrate.odeint
        s = np.arange(s0,s1+ds,ds)
        print 'Running solver ...'
        return sc.odeint(f,u0,s,args=(C,u,v))
    else: # use any other solver from scipy.integrate.ode
        r = sc.ode(f).set_integrator(solver) # vode,zvode,lsoda,dopri5,dop853
        r.set_f_params(C,u,v)
        r.set_initial_value(u0)
        #t = []
        y = []
        print 'Running solver ...'
        while r.successful() and r.t <= s1:
            r.integrate(r.t + ds)
            y.append(r.y)#; t.append(r.t)
        return np.array(y)

The problem I am experiencing is the following. If I decide to use the solver from scipy.integrate.odeint, then the parameters fshould be specified in the order indicated in the code. However, if I decide to use solvers from scipy.integrate.ode, I need to change the order of the function parameters f(y,s,C,u,v)to f(s,y,C,u,v), otherwise I will get an error

TypeError: 'float' object has no attribute '__getitem__'

If I do this, it will scipy.integrate.odeintgenerate the same error for f, which is defined as f(s,y,C,u,v). How can I work with unified fregardless of the order of parameters?

Edit:

To summarize the problem up:

scipy.integrate.ode , f f(s,y,C,u,v), scipy.integrate.odeint , f f(y,s,C,u,v). , ?

:

Scipy - 0.16.0

+5
1

, ?

- API, . odeint ode .

, , , , , ode. , :

    r = sc.ode(f).set_integrator(solver)

    r = sc.ode(lambda t, x, *args: f(x, t, *args)).set_integrator(solver)

: SciPy 1.1.0 tfirst scipy.integrate.odeint. , tfirst=False, . tfirst=True, odeint , func t (.. ). tfirst=True, func ode, odeint solver_ivp.

+6

Source: https://habr.com/ru/post/1614450/


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