I am new to Gulp, but following this tutorial, I set up the Gulp task, which is designed to view javascript files in a specific directory and transfer them to another directory - quite simply. I looked at several other lessons, but this method seemed to me the most concise. Here is my code:
var gulp = require('gulp');
var browserify = require('browserify');
var transform = require('vinyl-transform');
gulp.task('js', function() {
var browserified = transform(function(filename) {
return browserify(filename).bundle();
});
return gulp.src(['./public/js/src/**/*.js'])
.pipe(browserified)
.pipe(gulp.dest('./public/js/dist'));
});
The above code is very similar to many other implementations of this kind that I have seen, but when I try to run it with gulp js
, it gives the following error:
[15:47:13] Using gulp file
~/development/launchpad/workshop/gulpfile.js
[15:47:13] Starting 'js'...
_stream_readable.js:540
var ret = dest.write(chunk);
^
TypeError: undefined is not a function
at Producer.ondata (_stream_readable.js:540:20)
at Producer.emit (events.js:107:17)
at Producer.Readable.read (_stream_readable.js:373:10)
at flow (_stream_readable.js:750:26)
at resume_ (_stream_readable.js:730:3)
at _stream_readable.js:717:7
at process._tickCallback (node.js:355:11)
- , ?
( , , , _stream_readable.js Spotlight 20 , , -, Node ?)