Temporarily retrieve an image using the query library

Question

I am writing a web scraper, than I need to clear only the thumbnail image from the URL.

This is my function using urlib library.

def create_thumb(self):
    if self.url and not self.thumbnail:
        image = urllib.request.urlretrieve(self.url)

        # Create the thumbnail of dimension size
        size = 350, 350
        t_img = Imagelib.open(image[0])
        t_img.thumbnail(size)

        # Get the directory name where the temp image was stored
        # by urlretrieve
        dir_name = os.path.dirname(image[0])

        # Get the image name from the url
        img_name = os.path.basename(self.url)

        # Save the thumbnail in the same temp directory
        # where urlretrieve got the full-sized image,
        # using the same file extention in os.path.basename()
        file_path = os.path.join(dir_name, "thumb" + img_name)
        t_img.save(file_path)

        # Save the thumbnail in the media directory, prepend thumb
        self.thumbnail.save(
            os.path.basename(self.url),
            File(open(file_path, 'rb')))

for various reasons I need to change this to use a query library, what would be the equivalent for temporarily saving an image?

Answer 1

You can skip saving to the temporary part of the file and use the corresponding response object directly to create the image:

#!/usr/bin/env python3
import urllib.request
from PIL import Image # $ pip install pillow

im = Image.open(urllib.request.urlopen(url))
print(im.format, im.mode, im.size)

Here is requestsanalog:

#!/usr/bin/env python
import requests # $ pip install requests
from PIL import Image # $ pip install pillow

r = requests.get(url, stream=True)
r.raw.decode_content = True # handle spurious Content-Encoding
im = Image.open(r.raw)
print(im.format, im.mode, im.size)

Pillow 2.9.0 requests 2.7.0. Pillow 2.8.

Answer 2

io.BytesIO:

import requests

from PIL import Image
from io import BytesIO

r = requests.get(self.url)
b = BytesIO(r.content)
size = 350, 350
img = Image.open(b)
img.thumbnail(size)
img.save("foo.thumbnail", "JPEG")