Simulation / game with coins in Java

Question

Currently, I am taking a course in computer science, which is technically for beginners, but I feel that all the tasks they give me are more difficult than I can handle.

This quest requires me to simulate a coin. Three players play the game, and each of them has special requirements for victory:

• One wins if there are 2 heads of results and the total number of throws even
• One wins if there are 2 results, and the total number of views is
• One wins if there are 2 results: tails or heads, and the total number of throws is odd

What I have to do is run the experiment 300 times. Each time I have to determine which of the three won and how many times. And I'm really stuck. I have almost no code, but I have a very general idea of ​​what the code should be, but I can’t put it in Java.

For my appointment, I need to display the binary sequence that made the person win.

My idea:

• Initialize a counter (1, 2, 3) for each person so that I can track how many times they win.
• Initialize head count and tail counts to track randomly generated sequences.
• for . , , 300 , if, , . if , . System.out.println(); .
• ,

EDIT: , , , ! , , , . , ; 300 , , . , , , reset . , . - ?

EDIT: . , 300 ! . ; 1 , , , 2 . , , 1 , . - if?

import java.util.Random;

public class Assignment3e
{
public static void main(String[] args)
{                
    int counter1 = 0;
    int counter2 = 0;
    int counter3 = 0;

    Random coin = new Random();


    for(int i = 0; i <= 300; i++){
        int headCount = 0;
        int tailsCount = 0;
        for(int coinToss = 0; coinToss <= 3; coinToss++){
            int random = (int) (Math.random() * 6) + 1;
            String binary = Integer.toBinaryString(random);

          boolean result = coin.nextBoolean();
          if(result){
              headCount++;
              }
              else{
                  tailsCount++;
                  }
         if(headCount == 2 && binary.length() % 2 ==0){
                //Amy wins
                counter1 = counter1 + 1;
                System.out.println(binary + " Amy wins.");
            }
            else if(tailsCount == 2 && binary.length() % 2 == 0){
                //Penny wins
                counter2 = counter2 + 1;
                System.out.println(binary + " Penny wins.");
            }
            else if(headCount == 2 || tailsCount == 2 && binary.length() % 2 != 0){
                //Bernie wins
                counter3 = counter3 + 1;
                System.out.println(binary + " Bernie wins.");
            }
         }
      }
        System.out.println("Amy wins " + counter1 + " times.");
        System.out.println("Penny wins " + counter2 + " times.");
        System.out.println("Bernie wins " + counter3 + " times.");
}

}

Answer 1

.

, OP .

for 3 , 2 2 , 10.

: : 1 1 , 3- (Bernie)

, , 0 1, , 0.5 , headCount, tailCount. ( ).

, .

: : , headCount tailCount. , , reset.

:)

Edit: OP jsut , , .

, 1 - , 0 - . 3 , , Bernie. random, , 3 (1 = 1 ).

random 0 7.

, coinToss for. , , , (11 2- , 00 2- , )

Answer 2

, , :

• headCount tailCount . , , .

  , .

• , nextBoolean , . :

  boolean result = coin.nextBoolean(); // this renames dice to coin
  if(result) {
      headCount++;
  } else {
      tailCount++;
  }
  

• ( 1). , sum j, , coinTosses.

Answer 3

If you accidentally use a Random () object for the nextBoolean () coin, why not replace it int random = (int) (Math.random() * 6) + 1;with int random = coin.nextInt([range here])?