How to skip index in python for loop

Question

I have a list like this:

array=['for','loop','in','python']

for arr in array:
    print arr

It will give me a way out

for
lop
in
python

I want to print

in
python

How can I skip the first 2 indexes in python?

Answer 1

Code:

array=['for','loop','in','python']
for arr in array[2:]:
    print arr

Output:

in
python

Answer 2

Use slicing .

array = ['for','loop','in','python']

for arr in array[2:]:
    print arr

When you do this, the starting index in the loop forwill become 2. Thus, the output will be:

in
python

For more information, slicingread the following: Explain Python fragment notation

Answer 3

. Python:

for arr in array[2:]:
    print arr

Answer 4

,

:

for i ,j in enumerate(array):
    if i not in (1,2):
        print j

:

for
python

Answer 5

, , itertools.islice:

import itertools
array = 'for loop in python'.split()
for x in itertools.islice(array, 2, None):
    print x

because the slice statement creates a completely new list, which means overhead if you just want to iterate over it.