Is it mandatory to return gulp.src ()?

Question

I'm confused at gulp.src().

In accordance with this thread, I would suggest that you need to return gulp.src() .

The gulp project examples always return gulp.src(). i.e. gulp input sample .

However, many plugins display documentation that does not return gulp.src(). i.e.: gulp-less or gulp-angular-templatecache

How can I decide whether to return my gulp.src () task?

Answer 1

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, , - ; merge-stream:

var merge = require('merge-stream');

gulp.task('task', function () {
    var someOperation = gulp.src('./').pipe(gulp.dest('out'));
    var someOtherOperation = gulp.src('./assets').pipe(gulp.dest('out/assets'));

    return merge(someOperation, someOtherOperation);
});

... , . README, .

Answer 2

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