You can use a generatorall expression :
all(1 in x for x in (a, b, c, d))
Demo:
>>> a = [1 ,2]
>>> b = [1, 3]
>>> c = [1, 4]
>>> d = [2, 5]
>>> all(1 in x for x in (a, b, c, d))
False
>>> all(1 in x for x in (a, b, c))
True
>>>
In addition to being more readable, this solution is more efficient because it uses a lazy rating. He will check only as many elements as necessary to determine the result.
In addition, there was never a good reason:
True if 1 in l else False
- , in . :
1 in l
:
1 not in l