Bash script rename multiple files

Question

Let's say I have a bunch of files with a name something like this: bsdsa120226.nai bdeqa140223.nai, and I want to rename them to 120226.nai 140223.nai. How can I achieve this using the script below?

#!/bin/bash
name1=`ls *nai*`
names=`ls *nai*| grep -Po '(?<=.{5}).+'`
for i in $name1
    do
    for y in $names
        do
            mv $i $y
        done
    done



Solution:
name1=`ls *nai*`

for i in $name1
do
y=$(echo "$i" | grep -Po '(?<=.{5}).+')
mv $i $y
done

Answer 1

Using only bash, you can do this:

for file in *nai* ; do
  echo mv -- "$file" "${file:5}"
done

_{(Remove echowhen it is satisfied with the exit.)}

Avoid lsin scenarios other than displaying information. Use regular globbing instead.

See also How to perform string manipulations in bash? for stricter manipulation methods.

---

script : 5 , mv ( ), , .. lockstep. ( , .)

Answer 2

:

#!/bin/bash

shopt -s extglob nullglob
for file in *+([[:digit:]]).nai; do
    echo mv -nv -- "$file" "${file##+([^[:digit:]])}"
done

echo, mv.

. , 5 . .

Answer 3

rename (prename ), Perl :

prename 's/^.{5}//' *.nai

, script , , .

If you need to limit yourself to using this script, you need to work out one target file for each source file, for example:

#!/bin/bash
for i in *.nai; do
    y=$(echo "$i" | cut -c6-)
    mv "$i" "$y"
done

Answer 4

If your system has a tool rename, it’s better to go to a simple command rename,

rename 's/^.{5}//' *.nai

It just removes the first 5 characters from the file name.

OR

for i in *.nai; do mv "$i" $(grep -oP '(?<=^.{5}).+' <<< "$i"); done