No, they both compile the same way.
Itβs easier to see if you really give the lambda body something that depends on the state - otherwise the compiler caches one delegate instance for each lambda. But for example:
using System;
class Test
{
bool value = DateTime.Now.Hour == 10;
void Cast()
{
if (((Func<bool>)(() => value))())
{
Console.WriteLine("Yes");
}
}
void New()
{
if (new Func<bool>(() => value)())
{
Console.WriteLine("Yes");
}
}
static void Main()
{
new Test().Cast();
new Test().New();
}
}
Now IL for Cast:
.method private hidebysig instance void Cast() cil managed
{
// Code size 39 (0x27)
.maxstack 2
.locals init (bool V_0)
IL_0000: nop
IL_0001: ldarg.0
IL_0002: ldftn instance bool Test::'<Cast>b__0'()
IL_0008: newobj instance void class [mscorlib]System.Func`1<bool>::.ctor(object,
native int)
IL_000d: callvirt instance !0 class [mscorlib]System.Func`1<bool>::Invoke()
IL_0012: ldc.i4.0
IL_0013: ceq
IL_0015: stloc.0
IL_0016: ldloc.0
IL_0017: brtrue.s IL_0026
IL_0019: nop
IL_001a: ldstr "Yes"
IL_001f: call void [mscorlib]System.Console::WriteLine(string)
IL_0024: nop
IL_0025: nop
IL_0026: ret
} // end of method Test::Cast
and IL for New:
.method private hidebysig instance void New() cil managed
{
// Code size 39 (0x27)
.maxstack 2
.locals init (bool V_0)
IL_0000: nop
IL_0001: ldarg.0
IL_0002: ldftn instance bool Test::'<New>b__1'()
IL_0008: newobj instance void class [mscorlib]System.Func`1<bool>::.ctor(object,
native int)
IL_000d: callvirt instance !0 class [mscorlib]System.Func`1<bool>::Invoke()
IL_0012: ldc.i4.0
IL_0013: ceq
IL_0015: stloc.0
IL_0016: ldloc.0
IL_0017: brtrue.s IL_0026
IL_0019: nop
IL_001a: ldstr "Yes"
IL_001f: call void [mscorlib]System.Console::WriteLine(string)
IL_0024: nop
IL_0025: nop
IL_0026: ret
} // end of method Test::New
As you can see, they are the same except for a call ldftnthat simply uses the appropriate method created by the compiler.
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