Here is a minimal example of what I'm trying to do:
Create 3D Matrix
a(:,:,1)=[
1 2 3 4 1;
2 3 7 1 4;
3 7 6 0 9;
0 3 2 8 1;
1 4 3 1 1]
a(:,:,2)=[
1 7 3 4 2;
2 9 2 3 1;
1 4 7 7 0;
1 2 3 4 1;
0 9 3 3 9]
a(:,:,3)=[
9 4 0 3 5;
1 2 3 4 1;
2 0 2 3 1;
1 4 2 1 1;
2 5 7 8 1]
a(:,:,4)=[
2 3 5 2 0
0 0 0 0 8
5 2 7 9 8
2 4 1 1 0
6 3 8 7 9]
a(:,:,5)=[
3 5 1 4 6;
3 2 8 0 0;
0 2 1 0 4;
5 4 5 5 6;
9 5 9 9 5]
Create 3D Template
b(:,:,1)=[
9 4 0;
1 2 3;
2 0 2]
b(:,:,2)=[
2 3 5;
0 0 0;
5 2 7]
b(:,:,3)=[
3 5 1;
3 2 8;
0 2 1]
Calculate cross-correlation ( three-dimensional cross-correlation in Matlab ). I think cross-correlation is the same as convolution with inverted pattern. It is right?
c=convn(a,b(end:-1:1,end:-1:1,end:-1:1));
Find Best Match Indices
[x y z] = ind2sub(size(c),find(c==max(c(:))));
x=x-(size(b, 1) - 1)/2
y=y-(size(b, 2) - 1)/2
z=z-(size(b, 3) - 1)/2
I read that you need to subtract half the size of the template of the final coordinates, but I do not have a link to a page with this information. However, I think that if there weren’t, then the returned coordinates would not be the place where the center of the template would be only in the corner of the template.
: x=2, y=2, z=4. Matlab x=4, y=4, z=4.
b(:,:,1)=[
9 2 3;
4 7 7;
2 3 4]
b(:,:,2)=[
2 3 4;
0 2 3;
4 2 1]
b(:,:,3)=[
0 0 0;
2 7 9;
4 1 1]
(x=3, y=3, z=3).
, ?