Scala check if string is defined in option and empty

Question

Given the following:

myOption: Option[String]

What is the most idiomatic way to check if a String value inside a parameter is empty (if it is not defined, then it should be considered empty)?

Is the myOption.getOrElse("").isEmptybest / cleanest way?

Answer 1

You can do

def foo(s: Option[String]) = s.forall(_.isEmpty)

or

def foo(s: Option[String]) = s.fold(true)(_.isEmpty)

foldhas 2 parameters in different lists. The first is for the case None, and the other is evaluated, if any String.

Personally, I would prefer the first solution, but in the second one it is very clear what you want to return truein the case None.

Some examples:

foo(Some(""))   //true
foo(Some("aa")) //false
foo(None)       //true

Answer 2

myOption.forall(_.isEmpty)

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