Find specific link text using bs4

Question

I am trying to clear a website and find all feed headers. I'm having trouble getting the tag text aI need. Here is an example html.

<td class="m" id="b1"><a href="/QSYcfT" id="c1" target="_blank" onClick="vPI('https://www.youtube.com/watch?v=BFNH-6K10Ic', 'QSYcfT', this.id); this.blur(); return false;">TF4 - Oreos</a> <a href="#" onClick="return lkP('1', 'QSYcfT');" id="x1"><font class="bp">(0)</font></a>
<td class="m" id="b2"><a href="/zXHNvp" id="c2" target="_blank" onClick="vPI('https://www.youtube.com/watch?v=0vjcGwZGBYI', 'zXHNvp', this.id); this.blur(); return false;">Awesome Game Boy Facts</a> <a href="#" onClick="return lkP('2', 'zXHNvp');" id="x2"><font class="bp">(0)</font></a>

I am trying to get text for each tag awith id cand print each in a new line.

My conclusion should look like this.

TF4 - Oreos
Awesome Game Boy Facts

So far I have tried.

soup = bs4.BeautifulSoup(html)
links = soup.find_all('a',{'id' : 'c'})
for link in links:
    print link.text

But he finds nothing and does not print?

Answer 1

You can pass a regular expression instead of an attribute value:

links = soup.find_all('a', {'id': re.compile('^c\d+')})

^means the beginning of a line, \d+matches one or more digits.

Demo:

>>> import re
>>> from bs4 import BeautifulSoup
>>> 
>>> html = """
... <tr>
...     <td class="m" id="b1"><a href="/QSYcfT" id="c1" target="_blank" onClick="vPI('https://www.youtube.com/watch?v=BFNH-6K10Ic', 'QSYcfT', this.id); this.blur(); return false;">TF4 - Oreos</a> <a href="#" onClick="return lkP('1', 'QSYcfT');" id="x1"><font class="bp">(0)</font></a></td>
...     <td class="m" id="b2"><a href="/zXHNvp" id="c2" target="_blank" onClick="vPI('https://www.youtube.com/watch?v=0vjcGwZGBYI', 'zXHNvp', this.id); this.blur(); return false;">Awesome Game Boy Facts</a> <a href="#" onClick="return lkP('2', 'zXHNvp');" id="x2"><font class="bp">(0)</font></a></td>
... </tr>
... """
>>> soup = BeautifulSoup(html)
>>> links = soup.find_all('a', {'id': re.compile('^c\d+')})
>>> for link in links:
...     print link.text
... 
TF4 - Oreos
Awesome Game Boy Facts

Answer 2

a c, c1 c2.

links = soup.find_all('a',{'id' : 'c1'})

a , c, :

import re

links = soup.findAll('a', {'id': re.compile('^c')})

Answer 3

You can pass a regex object inside a callfind_all()

import re
import bs4

html = '''
<td class="m" id="b1"><a href="/QSYcfT" id="c1" target="_blank" onClick="vPI('https://www.youtube.com/watch?v=BFNH-6K10Ic', 'QSYcfT', this.id); this.blur(); return false;">TF4 - Oreos</a> <a href="#" onClick="return lkP('1', 'QSYcfT');" id="x1"><font class="bp">(0)</font></a>
<td class="m" id="b2"><a href="/zXHNvp" id="c2" target="_blank" onClick="vPI('https://www.youtube.com/watch?v=0vjcGwZGBYI', 'zXHNvp', this.id); this.blur(); return false;">Awesome Game Boy Facts</a> <a href="#" onClick="return lkP('2', 'zXHNvp');" id="x2"><font class="bp">(0)</font></a>
'''

soup = bs4.BeautifulSoup(html)
for links in soup.find_all('a', {'id' : re.compile('^c') }):
    print ''.join(links.find_all(text=True))

Output

TF4 - Oreos
Awesome Game Boy Facts