Call IEnumerable.SelectMany

Question

Considering this:

open System.Linq

let iota n = [0..(n-1)]

the following produces an error:

[2; 3; 4].SelectMany(fun n -> iota n)

Is there a way to pass function values ​​to SelectMany?

Answer 1

You need to pass the result to seq<int>:

[2; 3; 4].SelectMany(fun n -> iota n :> int seq)

alternatively you can use List.collect:

[2; 3; 4] |> List.collect iota