How to find if numbers in R are continuous?

Question

I have a range of values

c(1,2,3,4,5,8,9,10,13,14,15)

And I want to find ranges where numbers get intermittent. All I want is the output:

(1,5)
(8,10)
(13,15)

I need to find breakpoints.

I need to do this in R.

Answer 1

Something like that?

x <- c(1:5, 8:10, 13:15) # example data
unname(tapply(x, cumsum(c(1, diff(x)) != 1), range)
# [[1]]
# [1] 1 5
# 
# [[2]]
# [1]  8 10
# 
# [[3]]
# [1] 13 15

Another example:

x <- c(1, 5, 10, 11:14, 20:21, 23)
unname(tapply(x, cumsum(c(1, diff(x)) != 1), range))
# [[1]]
# [1] 1 1
#
# [[2]]
# [1] 5 5
#
# [[3]]
# [1] 10 14
#
# [[4]]
# [1] 20 21
#
# [[5]]
# [1] 23 23

Answer 2

x <- c(1:5, 8:10, 13:15)    
rr <- rle(x - seq_along(x))
rr$values <- seq_along(rr$values)
s <- split(x, inverse.rle(rr))
s
# $`1`
# [1] 1 2 3 4 5
# 
# $`2`
# [1]  8  9 10
# 
# $`3`
# [1] 13 14 15

## And then to get *literally* what you asked for:
cat(paste0("(", gsub(":", ",", sapply(s, deparse)), ")"), sep="\n")
# (1,5)
# (8,10)
# (13,15)

Answer 3

seqle, . cgwtools SO , .

Answer 4

, , diff/cumsum/range :

x  <- c(1:5, 8:10, 13:15)
x. <- c(0, cumsum( diff(x)-1 ) ) 

lapply( split(x, x.), range )